RS Aggarwal 2021-2022 for Class 6 Maths Chapter 6- Simplification
RS Aggarwal Class 6 Math Solution Chapter 6- Simplification Exercise 6B is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.
Rs Aggarwal Class 6 Math Solution Chapter 6- Simplification
Exercise 6B
OBJECTIVE QUESTIONS
Marks (✓) against the correct answer in each of the following:
1. 8 + 4 ÷ 2 × 5 = ?
(a) 30 (b) 50 (c) 18 (d) none of these
Solution: Correct option is (c) 18
8 + 4 ÷ 2 × 5
= 8 + 2 × 5
= 8 + 10 = 18
2. 54 ÷ 3 of 6 + 9 = ?
(a) 117 (b) 12 (c) `frac\{6}{5}` (d) none of these
Solution: Correct option is (b) 12
= 54 ÷ 3 of 6 + 9
= 54 ÷ (3 x 6) + 9
= 54 ÷ 18 + 9
= 3 + 9 = 12
3. 13 - (12 - 6 ÷ 3) = ?
(a) 11 (b) 3 (c) `frac\{7}{3}` (d) none of these
Solution: Correct option is (b) 3
= 13 − (12 − 6 ÷ 3)
= 13 − (12 − 2)
= 13 − 10 = 3
4. 1001 ÷ 11 of 13 = ?
(a) 7 (b) 1183 (c) 847 (d) none of these
Solution: Correct option is (a) 7
= 1001 ÷ 11 of 13
= 1001 ÷ ( 11 x 13)
= 1001 ÷ 143 = 7
5. 133 + 28 ÷ 7 - 8 × 2 = ?
(a) 7 (b) 121 (c) 30 (d) none of these
Solution: Correct option is (b) 121
= 133 + 28 ÷ 7 − 8 × 2
= 133 + 4 − 8 × 2
= 133 + 4 − 16
= 137 − 16
= 121
6. 3640 − 14 ÷ 7 × 2 = ?
(a) 3636 (b) 1036 (c) 1819 (d) none of these
Solution: Correct option is (a) 3636
= 3640 − 14 ÷ 7 × 2
= 3640 − 2 × 2
= 3640 − 4
= 3636
7. 100 × 10 − 100 + 2000 ÷ 100 = ?
(a) 29 (b) 920 (c) none of these
Solution: Correct option is (b) 920
= 100 × 10 − 100 + 2000 ÷ 100
= 100 × 10 − 100 + 20
= 1000 − 100 + 20
= 1020 −100
= 920
8. 27 − [18 − {16 − (5 − `bar(4−1)`)}] = ?
(a) 25 (b) 23 (c) none of these
Solution: Correct option is (b) 23
27 − [18 − {16 − (5 − `bar(4−1)`)}]
= 27 − [18 − {16 − (5 − 3)}]
= 27 − [18 − {16 − 2}]
= 27 − [18 − 14]
= 27 − 4
= 23
9. 32 − [48 ÷ {36 − ( 27 − `bar(16−9)`)} = ?
(a) 29 (b) `frac\{520}{17}` (c) none of these
Solution: Correct option is (a) 29
32 − [48 ÷ {36 − ( 27 − `bar(16−9)`)}
= 32 − [48 ÷ {36 − ( 27 − 7)}]
= 32 − [48 ÷ {36 −20}]
= 32 − [48 ÷ 16]
= 32 − 3
= 29
10. 8 − [28 ÷ {34 − (36 − 18 ÷ 9 × 8)}] = ?
(a) 6 (b) 6`frac\{4}{9}` (c) none of these
Solution: Correct option is (a) 6
8 − [28 ÷ {34 − (36 − 18 ÷ 9 × 8)}]
= 8 − [28 ÷ {34 − (36 − 2 × 8)}]
= 8 − [28 ÷ {34 − (36 − 16)}]
= 8 − [28 ÷ {34 − 20}]
= 8 − [28 ÷ 14]
= 8 − 2 = 6
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