RS Aggarwal Class 6 Maths Solutions Chapter 8- Algebraic Expressions Exercise 8A

RS Aggarwal 2021-2022 for Class 6 Maths Solutions Chapter 8- Algebraic Expressions

RS Aggarwal Class 6 Math Solution Chapter 8-Algebraic Expressions Exercise 8A is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily.  RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.

 Rs Aggarwal Class 6 Math Solution Chapter 8- Algebraic Expressions 

Exercise 8A

1: Write the following using literals, numbers and signs of basic operations:

    (i) x increased by 12

    (ii) y decreased by 7

    (iii) The difference of a and b, when a > b

    (iv) The product of x and y added to their sum

    (v) One third of x multiplied by the sum of a and b

    (vi) 5 times x added to 7 times y

    (vii) Sum of x and quotient of y by 5

    (viii) x taken away from 4

    (ix) 2 less than the quotient of x by y

    (x) `x` multiplied by itself

    (xi) Twice x increased by y

    (xii) Thrice `x` added to y squared

    (xiii) `x` minus twice y

    (xiv) x cubed less than y cubed.

    (xv) Quotient of x by 8 is multiplied by y

Solution:

    (i) x increased by 12 is (x + 12).

    (ii) y decreased by 7 is (y - 7).

    (iii) The difference of a and b, when a>b is (a - b).

    (iv) The product of x and y is xy.         The sum of x and y is (x + y).   So, product of x and y added to their sum is xy + (x + y)

    (v) One third of x is `frac\{x}{3}`.         The sum of a and b is (a + b). ∴ One-third of x multiplied by the sum of a and b = `frac\{x}{3}` × (a + b) = `frac\{x(a+b)}{3}`

    (vi) 5 times `x` added to 7 times y = (5 × x) + (7 × y), which is equal to 5x + 7y.

    (vii) Sum of `x` and the quotient of y by 5 is `x` + `frac\{y}{5}`.

    (viii) `x` taken away from 4 is (4 − `x`).

    (ix) 2 less than the quotient of `x` by y is `frac\{x}{y}`− 2.

    (x) `x` multiplied by itself is `x` × `x` = `x^2`.

    (xi) Twice `x` increased by y is (2 × x) + y = 2`x` + y.

    (xii) Thrice `x` added to y squared is (3 × x) + (y × y) = 3x + `y^2`.

    (xiii) `x` minus twice y is x − (2 × y) = x − 2y.

    (xiv) `x` cubed less than y cubed is (y × y × y)  − (x × x × x) = `y^3` − `x^3`.

    (xv) The quotient of  `x` by 8 is multiplied by y is `frac\{x}{8}` × y = `frac\{xy}{8]`.

2: Ranjit scores 80 marks in English and x marks in Hindi. What is his total score in the two subjects?

Solution:

    Marks scored in English = 80

    Marks scored in Hindi = `x`

    Total score in the two subjects = 80 + `x`

3: Write the following in exponential form: 

    (i) b × b × b × …….. 15 times

    (ii) y × y × y × …….. 20 times

    (iii) 14 × a × a × a × a × b × b×  b

    (iv) `6 × x × x × y × y`

    (v) `3 × z × z × z × y × y × x`

Solution: 

    (i) `b^15`

    (ii) `y^20`

    (iii) 14`a^4b^3`

    (iv) 6`x^2y^2`

    (v) 3`z^3y^2x`

4: Write down the following in product form:

    (i) `x^2y^4`

    (ii) `6y^5`

    (iii) `9xy^2z`

    (iv) `10a^3b^3c^3`

Solution:

    (i) `x` × `x` × y × y × y × y

    (ii) 6 × y × y × y × y × y

    (iii) 9 × `x` × y × y × z

    (iv) 10 × a × a × a × b× b × b × c × c × c