RS Aggarwal 2021-2022 for Class 6 Maths Chapter 3 - Whole Number
Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.
Class 6 RS Aggarwal Maths Chapter 3 - Whole Number
Exercise 3A
1: Write the next three whole numbers after 30999.
Solution:
After 30999, three whole numbers will be
30999+1=31000
31000+1=31001
31001+1=31002
ie., 31000, 31001 and 31002
2: Write the three whole numbers occurring just before 10001.
Solution:
Three whole numbers occurring just before 10001 are as follows:
10001 − 1 = 10000
10000 − 1 = 9999
9999 − 1 = 9998
∴ The three whole numbers just before 10001 are 10000, 9999 and 9998.
3: How many whole numbers are there between 1032 and 12097
Solution:
Number of whole numbers between 1032 and 1209 = (1209 − 1032) − 1
= 177 − 1
= 176
4: Which is the smallest whole number?
Solution:
0 (zero) is the smallest whole number.
All the natural numbers along with 0 are called whole numbers.
5: Write the successor of
(i) 2540801
(ii) 9999
(iii) 50904
(iv) 61639
(v) 687890
(vi) 5386700
(vii) 6475999
(viii) 9999999
Solution:
(i) Successor of 2540801 = 2540801 + 1 = 2540802
(ii) Successor of 9999 = 9999 + 1 = 10000
(iii) Successor of 50904 = 50904 + 1 = 50905
(iv) Successor of 61639 = 61639 + 1 = 61640
(v) Successor of 687890 = 687890 + 1 = 687891
(vi) Successor of 5386700 = 5386700 + 1 = 5386701
(vii) Successor of 6475999 = 6475999 + 1 = 6476000
(viii) Successor of 9999999 = 9999999 + 1 = 10000000
6: Write the predecessor of
(i) 97
(ii) 10000
(iii) 36900
(iv) 7684320
(v) 1566391
(vi) 2456800
(vii) 100000
(viii) 1000000
Solution:
(i) Predecessor of 97 = 97 − 1 = 96
(ii) Predecessor of 10000 = 10000 − 1 = 9999
(iii) Predecessor of 36900 = 36900 − 1 = 36899
(iv) Predecessor of 7684320 = 7684320 − 1 = 7684319
(v) Predecessor of 1566391 = 1566391 − 1 = 1566390
(vi) Predecessor of 2456800 = 2456800 − 1 = 2456799
(vii) Predecessor of 100000 = 100000 − 1 = 99999
(viii) Predecessor of 1000000 = 1000000 − 1 = 999999
7: Write down the three consecutive whole numbers just preceding 7510001.
Solution:
The three consecutive whole numbers just preceding 7510001 are as follows:
7510001 − 1 = 7510000
7510000 − 1 = 7509999
7509999 − 1 = 7509998
∴ The three consecutive numbers just preceding 7510001 are 7510000, 7509999 and 7509998.
8: Write (T) for trac and (F) for faise against each of the following statements:
(i) Zero is the smallest natural number.
(ii) Zero is the smallest whole number,
(iii) Every whole number is a natural number
(iv) Every natural number is a whole number.
(v) 1 is the smallest whole number.
(vi) The natural number 1 has no predecessor.
(vii) The whole number 1 has no predecessor.
(viii) The whole number 0 has no predecessor
(ix) The predecessor of a two-dipt number is never a single-digit number.
(x) The successor of a two-digit number is always a two-digit number.
(xi) 500 is the predecessor of 499.
(xii) 7000 is the successor of 6999.
Solution:
(i) False. 0 is not a natural number.1 is the smallest natural number.
(ii) True.
(iii) False. 0 is a whole number but not a natural number.
(iv) True. Natural numbers include 1,2,3 ..., which are whole numbers.
(v) False. 0 is the smallest whole number.
(vi) True. The predecessor of 1 is 1 − 1 = 0, which is not a natural number.
(vii) False. The predecessor of 1 is 1 − 1 = 0, which is a whole number.
(viii) True. The predecessor of 0 is 0 − 1 = −1, which is not a whole number.
(ix) False. The predecessor of a two-digit number can be a single digit number. For example, the predecessor of 10 is 10 − 1, i.e., 9.
(x) False. The successor of a two-digit number is not always a two-digit number. For example, the successor of 99 is 99 + 1, i.e., 100.
(xi) False. The predecessor of 499 is 499 − 1, i.e., 498.
(xii) True. The successor of 6999 is 6999 + 1, i.e., 7000.
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