RS Aggarwal 2021-2022 for Class 6 Maths Chapter 5 - Fractions
RS Aggarwal Class 6 Math Solution Chapter 4- Fractions Exercise 5A is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.
Rs Aggarwal Class 6 Math Solution Chapter 5 - Fractions
Exercise 5A
1. Write the fraction representing the shaded portion:
2.Shade `frac\{4}{9}` of the figure.
Solution:
3. In the given figure, if we say that the shaded region is `frac\{1}{4}`, then identify the error in it.
The given rectangle is not divided into four equal parts.
4. Write a fraction for each of the following:
(i) three-fourths (ii) four-sevenths
(iii) two-fifths (iv) three-tenths
(v) one-eighths (vi) five-sixths
(vii) eight-ninths (viii) seven-twelfths
Solution:
(i) `frac\{3}{4}` (ii) `frac\{4}{7}`
(iii) `frac\{2}{5}` (iv) `frac\{3}{10}`
(v) `frac\{1}{8}` (vi) `frac\{5}{6}`
(vii) `frac\{8}{9}` (viii) `frac\{7}{12}`
5. Write down the numerator and the denominator of each of the fractions given below:
(i) `frac\{4}{9}` (ii) `frac\{6}{11}` (iii) `frac\{8}{15}` (iv) `frac\{12}{17}` (v) `frac\{5}{1}`
Solution:
(i) In `frac\{4}{9}` , Numerator = 4 and Denominator = 9.
(ii) In `frac\{6}{11}` , Numerator = 6 and Denominator = 11.
(iii) In `frac\{8}{15}` , Numerator = 8 and Denominator = 15.
(iv) In `frac\{12}{17}` , Numerator = 12 and Denominator = 17.
(v) In `frac\{5}{1}` , Numerator = 5 and Denominator = 1.
6. Write down the fraction in which
(i) numerator = 3, denominator = 8 (ii) numerator = 5, denominator = 12
(iii) numerator = 7, denominator = 16 (iv) numerator = 8, denominator = 15
Solution:
(i) `frac\{3}{8}` (ii) `frac\{5}{12}` (iii) `frac\{7}{16}` (iv) `frac\{8}{15}`
7. Write down the fractional number for each of the following:
(i) `frac\{2}{3}` (ii) `frac\{4}{9}` (iii) `frac\{2}{5}` (iv) `frac\{7}{10}` (v) `frac\{1}{3}`
(vi) `frac\{3}{4}` (vii) `frac\{3}{8}` (viii) `frac\{9}{14}` (ix) `frac\{5}{11}` (x) `frac\{6}{15}`
Solution:
(i) two-thirds (ii) four−ninths
(iii) two−fifths (iv) seven−tenths
(v) one−thirds (vi) three−fourths
(vii) three−eighths (viii) nine−fourteenths
(ix) five−elevenths (x) six−fifteenths
8. What fraction of an hour is 24 minutes?
Solution:
We know: 1 hour = 60 minutes
∴ The required fraction = `frac\{24}{60}` = `frac\{2}{5}`
9. How many natural numbers are there from 2 to 10 ? What fraction of them are prime numbers?
Solution:
There are total 9 natural numbers from 2 to 10. They are 2, 3, 4, 5, 6, 7, 8, 9, 10.
Prime number between 2 to 10 are 2, 3, 5, 7 .
∴ The required fraction of prime number = `frac\{4}{9}`
10. Determine:
(i) `frac\{2}{3}` of 15 pens (ii) `frac\{2}{3}` of 27 balls (iii) `frac\{2}{3}` of 36 balloons
Solution:
(i) `frac\{2}{3}` of 15 pens = `frac\{2}{cancel 3^1}` x `cancel{15}^5` = 10 pens.
(ii) `frac\{2}{3}` of 27 balls = `frac\{2}{cancel 3^1}` x `cancel{27}^9` = 18 balls.
(iii) `frac\{2}{3}` of 36 balloons = `frac\{2}{cancel 3^1}` x `cancel{36}^12` = 24 balloons.
11. Determine:
(i) `frac\{3}{4}` of 16 cups (ii) `frac\{3}{4}` of 28 rackets (iii) `frac\{3}{4}` of 32 books
Solution:
(i) `frac\{3}{4}` of 16 cups = `frac\{3}{cancel 4^1}` x `cancel{16}^4` = 12 cups.
(ii) `frac\{3}{4}` of 28 rackets = `frac\{3}{cancel 4^1}` x `cancel{28}^7` = 21 rackets.
(iii) `frac\{3}{4}` of 32 books = `frac\{3}{cancel 4^1}` x `cancel{32}^8` = 24 books.
12. Neelam has 25 pencils. She gives `frac\{4}{5}` of them to Meena. How many pencils does Meena get ? How many pencils are left with Neelam?
Solution:
Neelam has total pencils = 25
Pencils given to Meena = `frac\{4}{5}` of 25
= `frac\{4}{cancel 5^1}` x `cancel{25}^5`
= 20 pencils
No. of pencils left with Neelam = 25 – 20 = 5
13. Represent each of the following fractions on the number line:
(i) `frac\{3}{8}` (ii) `frac\{5}{9}` (iii) `frac\{4}{7}` (iv) `frac\{2}{5}` (v) `frac\{1}{4}`
Solution:
(i) Take a line segment OA = 1 unit of length
Divide them into 8 equal parts and take 3 parts at P, then P represents `frac\{3}{8}`.
(ii) Take a line segment OA = 1 unit of length
Divide them into 9 equal parts and take 5 parts at P, then P represents `frac\{5}{9}`.
(iii) Take a line segment OA = 1 unit of length
Divide them into 7 equal parts and take 4 parts at P, then P represents `frac\{4}{7}`.
(iv) Take a line segment OA = 1 unit of length
Divide them into 5 equal parts and take 2 parts at P, then P represents `frac\{2}{5}`.
(v) Take a line segment OA = 1 unit of length
Divide them into 4 equal parts and take 1 parts at P, then P represents `frac\{1}{4}`.
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