RS Aggarwal 2021-2022 for Class 6 Maths Chapter 3 - Whole Number
Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number Exercise 3F is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.
Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number
Exercise 3F
1: The smallest whole number is
(a) 1
(b) 0
(c) 2
(d) none of these
Solution: Correct option is (b) 0
2: The least number of 4 digits which is exactly divisible by 9 is
(a) 1018
(b) 1026
(c) 2009
(d) 1008
Solution: Correct option is (d) 1008
(a) 999980
(b) 999982
(c) 999984
(d) 999964
Solution: Correct option is (c) 999984
The largest 6 digit number = 999999
Now, first we divide 999999 by 16
4: What least number should be subtracted from 10004 to get a number exactly divisible by 12?
(a) 4
(b) 6
(c) 8
(d) 20
Solution: Correct option is (c) 8
Now, First we divide 10004 by 12
5: What least number should be added to 10056 to get a number exactly divisible by 23?
(a) 5
(b) 18
(c) 13
(d) 10
Solution: Correct option is (b) 18
Now, First we divide 10056 by 23
Remainder is 5
So, require least number = 23 - 5 = 18
6: What whole number is nearest to 457 which is divisible by 11?
(a) 450
(b) 451
(c) 460
(d) 462
Solution: Correct option is (d) 462
Now, First we divide 457 by 11.
So, The number nearest to 457 which is divisible 11 will be = 457 – 6 + 11
= 457 + 5
= 462
7: How many whole numbers are there between 1018 and 1203?
(a) 185
(b) 186
(c) 184
(d) none of these
Solution: Correct option is (c) 184
Number of whole numbers = (1203 - 1018) - 1
= 185 - 1 = 184
8: A number when divided by 46 gives 11 as quotient and 15 as remainder. The number is
(a) 491
(b) 521
(c) 701
(d) 679
Solution: Correct option is (b) 521
Divisor = 46
Quotient =11
Remainder =15
Require Number = Divisor x Quotient + Remainder
= 46 × 11 + 15
= 506 + 15
= 521
9: In a division sum, we have dividend 199, quotient 16 and remainder 7. The divisor is
(a) 11
(b) 23
(c) 12
(d) none of these
Solution: Correct option is (c) 12
Dividend = 199
Quotient = 16
Remainder = 7
Divisor = (Dividend - Remainder) ÷ Quotient
= (199 - 7) ÷ 16
= 192 ÷ 16
= 12
10: 7589 - ? = 3434
(a) 11023
(b) 4245
(c) 4155
(d) none of these
Solution: Correct option is (c) 4155
Require Number = 7589 - 3434
= 4155
11: 587 × 99 = ?
(a) 57213
(b) 58513
(c) 58113
(d) 56413
Solution: Correct option is (c) 58113
587 × 99
= 587 × (100 – 1)
= 587 × 100 – 587 × 1
= 58700 – 587
= 58113
12: 4 × 538 × 25 = ?
(a) 32280
(b) 26900
(c) 53800
(d) 10760
Solution: Correct option is (c) 53800
4 × 538 × 25
= 538 × 4 × 25
= 538 × 100
= 53800
13: 24679 × 92 + 24679 × 8 = ?
(a) 493580
(b) 1233950
(c) 2467900
(d) none of these
Solution: Correct option is (c) 2467900
24679 × 92 + 24679 × 8
= 24679 × (92 + 8)
= 24679 × 100
= 2467900
14: 1625 × 1625 - 1625 × 625 = ?
(a) 1625000
(b) 162500
(c) 325000
(d) 812500
Solution: Correct option is (a) 1625000
1625 × 1625 – 1625 × 625
= 1625 (1625 – 625)
= 1625 × 1000
= 1625000
15: 1568 × 185 - 1568 × 85 = ?
(a) 7840
(b) 15680
(c) 156800
(d) none of these
Solution: Correct option is (c) 156800
1568 × 185 – 1568 × 85
= 1568 (185 – 85)
= 1568 × 100
= 156800
16: (888 + 111 + 555) = (111 × ?)
(a) 120
(b) 280
(c) 20
(d) 140
Solution: Correct option is (c) 20
888 + 111 + 555 = 111 x ?
= 111 (8 + 7 + 5)
= 111 × 20
17: The sum of two odd numbers is
(a) an odd number
(b) an even number
(c) a prime number
(d) a multiple of 3
Solution: Correct option is (b)
The sum of two odd number is an even number
18: The product of two odd numbers is
(a) an odd number
(b) an even number
(c) a prime number
(d) none of these
Solution: Correct option is (a)
The product of two odd numbers is an odd number
19: If a is a whole number such that a + a = a , then a = ?
(a) 1
(b) 2
(c) 3
(d) none of these
Solution: Correct option is (d)
If a is a whole number such that
a + a = a, then a = 0
as 0 + 0 = 0
20: The predecessor of 10000 is
(a) 10001
(b) 9999
(c) none of these
Solution: Correct option is (b)
The predecessor of 10000 = 10000 – 1
= 9999
21: The successor of 1001 is
(a) 1000
(b) 1002
(c) none of these
Solution: Correct option is (b)
The successor of 1001 = 1001 + 1
= 1002
22: The smallest even whole number is
(a) 0
(b) 2
(c) none of these
Solution: Correct option is (b)
The smallest even whole number is 2
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