RS Aggarwal 2021-2022 for Class 6 Maths Chapter 3 - Whole Number
Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.
Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number
Exercise 3C
1: Perform the following subtractions. Check your results by the corresponding additions:
(i) 6237 - 694
(ii) 21205 - 10899
(iii) 100000 -78987
(iv) 1010101 - 656565
Solution:
(i) 6 2 3 7 Check:- 5 5 4 3
- 6 9 4 - 6 9 4
5 5 4 3 6 2 3 7
(ii) 2 1 2 0 5 Check:- 1 0 3 0 6
-1 0 8 9 9 - 1 0 8 9 9
1 0 3 0 6 2 1 2 0 5
(iii) 1 0 0 0 0 0 Check:- 2 1 0 1 3
- 7 8 9 8 7 - 7 8 9 8 7
2 1 0 1 3 1 0 0 0 0 0
(iv) 1 0 1 0 1 0 1 Check:- 3 5 3 5 3 6
- 6 5 6 5 6 5 - 6 5 6 5 6 5
3 5 3 5 3 6 1 0 1 0 1 0 1
2. Replace each * by the correct digit each of the following:
(i) 9 1 7 (ii) 6 1 7 2
- * 5 * - * * 6 9
5 * 8 2 9 * *
(iii) 5 0 0 1 0 0 3 (iv) 1 0 0 0 0 0 0
- * * 6 9 8 7 - * * * * 1
4 8 4 * * * * * 7 0 4 2 *
Solution:
(i) 9 1 7 (ii) 6 1 7 2
- 3 5 9 - 3 2 6 9
5 5 8 2 9 0 3
(iii) 5 0 0 1 0 0 3 (iv) 1 0 0 0 0 0 0
- 1 5 6 9 8 7 - 2 9 5 7 1
4 8 4 4 0 1 6 9 7 0 4 2 9
3: Find the difference:
(i) 463 - 9
(ii) 5632 - 99
(iii) 8640 - 999
(iv) 13006 - 9999
Solution:
(i) 463 − 9
= 463 − 10 + 1
= 464 − 10
= 454
(ii) 5632 − 99
= 5632 − 100 + 1
= 5633 − 100
= 5533
(iii) 8640 − 999
= 8640 − 1000 + 1
= 8641 − 1000
= 7641
(iv) 13006 − 9999
= 13006 − 10000 + 1
= 13007 − 10000
= 3007
4: Find the difference between the smallest number of 7 digits and the largest number of 4 digits.
Solution:
The smallest number of 7 digits = 1000000
The largest number of 4 digits = 9999
∴ Their difference = 1000000 − 9999
=1000000 − 10000 + 1
=1000001 − 10000
=990001
5: Ravi opened his account in a bank by depositing Rs. 136000. Next day he withdrew Rs. 73129 from it. How much money was left in his account?
Solution:
Money deposited in bank = Rs 1,36,000
Money withdrawn from bank = Rs 73,129
Money left in his account = money deposited − money withdrawn
= Rs (136000 − 73129)
= Rs 62871
∴ Rs 62,871 is left in Ravi's account.
6: Mrs. Saxena withdrew Rs. 100000 from her bank account. She purchased a TV set for Rs. 38750, a refrigerator for Rs. 23890 and jewellery worth Rs. 35560. How much money was left with her?
Solution:
Money withdrawn by from bank = Rs 1,00,000
Cost of the TV set = Rs 38,750
Cost of the refrigerator = Rs 23,890
Cost of the jewellery = Rs 35,560
Total money spent = Rs (38750 + 23890 + 35560) = Rs 98200
Now, money left = money withdrawn − money spent
= Rs (100000 − 98200)
= Rs 1800
∴ Rs 1,800 is left with Mrs Saxena.
7: The population of a town was 110500. In one year it increased by 3608 due to new births. However, 8973 persons died or left the town during the year. What was the population at the end of the year?
Solution:
Population of the town = 110500
Increased population = 110500 + 3608 = 114108
Number of persons who died or left the town = 8973
Population at the end of the year = 114108 − 8973 = 105135
∴ The population at the end of the year will be 105135.
8: Find the whole number n when:
(i) n + 4 = 9
(ii) n + 35 = 101
(iii) n -18 = 39
(iv) n - 20568 = 21403
Solution:
(i) n + 4 = 9
⇒ n = 9 − 4 = 5
(ii) n + 35 = 101
⇒ n = 101 − 35 = 66
(iii) n - 18 = 39
⇒ n = 18 + 39 = 57
(iv) n − 20568 = 21403
⇒ n = 21403 + 20568 = 41971
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