RS Aggarwal Class 6 Maths Chapter 1 - Number System EXERCISE 1D

 RS Aggarwal 2021-2022 for Class 6 Maths Chapter 1 - Number System 

RS Aggarwal Class 6 Math Solution Chapter 1-  Number System Exercise 1D is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily.  RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.

 Rs Aggarwal Class 6 Math Solution Chapter 1- Number System 

EXERCISE 1D

1. Round each of the following numbers to the nearest ten: 

    (a) 36 (b) 173     (c) 3869 (d) 16378

Solution:-

    (a) Nearest ten of 36 is 40

    (b) Nearest ten of 173 is 170

    (c) Nearest ten of 3869 is 3870

    (d) Nearest ten of 16786 is 16380

2. Round each of the following numbers to the nearest hundred: 

    (a) 814 (b) 1254 (c) 43126 (d) 98165

Solution:-

    (a) Nearest hundred of 814 is 800

    (b) Nearest hundred of 1254 is 1300

    (c) Nearest hundred of 43126 is 43100

    (d) Nearest hundred of 98165 is 98200

3. Round each of the following numbers to the nearest thousand:

    (a) 793 (b) 4826 (c) 16719 (d) 28394

Solution:-

    (a) Nearest thousand of 793 is 1000

    (b) Nearest thousand of 4826 is 5000

    (c) Nearest thousand of 16719 is 17000

    (d) Nearest thousand of 28394 is 30000

4. Round each of the following numbers to the nearest ten thousand:

    (a) 17514 (b) 26340 (c) 34890 (d) 272685

Solution:-

    (a) Nearest ten thousand of 17514 is 20000

    (b)  Nearest ten thousand of 26340 is 30000

    (c)  Nearest ten thousand of 34890 is 30000

    (d)  Nearest ten thousand of 272685 is 270000

Estimate each sum to the nearest ten:

    5. (57+34)     6. (43 +78)     7. (14 +69)

    8. (86+19)     9. (95 +58)     10. (77 +63)

    11. (356+275) 12. (463 +182) 13. (538+276)

Solution:- 

    (5)    57 estimated to the nearest ten = 60

            34 estimated to the nearest ten = 30 

        ∴ The required estimation = (60 + 30) = 90

    (6)    43 estimated to the nearest ten = 40

            78 estimated to the nearest ten = 80

        ∴ The required estimation = (40 + 80) = 120

    (7)   14 estimated to the nearest ten = 10

           69 estimated to the nearest ten = 70

        ∴ The required estimation = (10 + 70) = 80

    (8)  86 estimated to the nearest ten = 90

           19 estimated to the nearest ten = 20

        ∴ The required estimation = (90 + 20) = 110

    (9)   95 estimated to the nearest ten = 100

            58 estimated to the nearest ten = 60

        ∴ The required estimation = (100 + 60) = 160

    (10)  77 estimated to the nearest ten = 80

            63 estimated to the nearest ten = 60

        ∴ The required estimation = (80 + 60) = 140

    (11)  356 estimated to the nearest ten = 360

            275 estimated to the nearest ten = 280

        ∴ The required estimation = (360 + 280) = 640

    (12)  463 estimated to the nearest ten = 460

            182 estimated to the nearest ten = 180

        ∴ The required estimation = (460 + 180) = 640

    (13)  538 estimated to the nearest ten = 540

            276 estimated to the nearest ten = 280

        ∴ The required estimation = (540 + 280) = 820

Estimate each sum to the nearest hundred:

    14. (236 + 689)      15. (458 + 324) 16. (170 + 395)

    17. (3280 + 4395)                    18. (5130 + 1410)              19. (10083 + 29380)

Solution:- 

    (14)  236 estimated to the nearest hundred = 200

            689 estimated to the nearest hundred = 700

         ∴ The required estimation = (200 + 700) = 900

    (15)  458 estimated to the nearest hundred = 500

            324 estimated to the nearest hundred = 300

        ∴ The required estimation = (500 + 300) = 800

    (16)  170 estimated to the nearest hundred = 200

            395 estimated to the nearest hundred = 400

        ∴ The required estimation = (200 + 400) = 600

    (17)  3280 estimated to the nearest hundred = 3300

            4395 estimated to the nearest hundred = 4400

        ∴ The required estimation = (3300 + 4400) = 7700

    (18)  5130 estimated to the nearest hundred = 5100

            1410 estimated to the nearest hundred = 1400

        ∴ The required estimation = (5100 + 1400) = 6500

    (19)  10083 estimated to the nearest hundred = 10100

            29380 estimated to the nearest hundred = 29400

       ∴ The required estimation = (10100 + 29400) = 39500

Estimate each sum to the nearest thousand:

    (20).   (32836 + 16466)                (21).   (46703 + 11375) 

    (22).  There are 54 balls in the box A and 79 balls in box B. Estimate the total number of balls in both the boxes taken together.

Solution:-  

    (20).   32836 estimated to the nearest thousand = 33000

              16466 estimated to the nearest thousand = 16000

           ∴ The required estimation = (33000 + 16000) = 49000

    (21).  46703 estimated to the nearest thousand = 47000

     

              11375 estimated to the nearest thousand = 11000

         ∴ The required estimation = (47000 + 11000) = 58000

    (22).  Number of balls in box A = 54

             Number of balls in box B = 79

             Estimated number of balls in box A = 50

             Estimated number of balls in box B = 80

         ∴ Total estimated number of balls in both the boxes = (50 + 80) = 130

Estimate each difference to the nearest ten:

    (23)  (53 - 18)                (24).  (97 - 38)            (25).  (409 - 148)

Solution:-

    (23).  We have,

              53 estimated to the nearest ten = 50

             18 estimated to the nearest ten = 20

           ∴ The required estimation = (50 ‒ 20) = 30

    (24).  97 estimated to the nearest ten = 100

             38 estimated to the nearest ten = 40

         ∴ The required estimation = (100 ‒ 40) = 60

    (25).  409 estimated to the nearest ten = 410

             148 estimated to the nearest ten = 150

          ∴ The required estimation = (410 ‒ 150) = 260

Estimate each difference to the nearest hundred:

    (26)  (678 - 215)          (27).  (957 - 578)        (28).  (7258 - 2429)        (29).  (5612 - 3095)

Solution:- 

    (26).  678 estimated to the nearest hundred = 700

            215 estimated to the nearest hundred = 200

         ∴ The required estimation = (700 ‒ 200) = 500

    (27).  957 estimated to the nearest hundred = 1000

             578 estimated to the nearest hundred = 600

          ∴ The required estimation = (1000 ‒ 600) = 400

    (28).  7258 estimated to the nearest hundred = 7300

              2429 estimated to the nearest  hundred = 2400

          ∴ The required estimation = (7300 ‒ 2400) = 4900

    (29).  5612 estimated to the nearest hundred = 5600

              3095 estimated to the nearest hundred = 3100

          ∴ The required estimation = (5600 ‒ 3100) = 2500

Estimate each difference to the nearest thousand:

    (30).  (35863 - 27677)                (31).  (47005 - 39488)

Solution:- 

    (30). 35863 estimated to the nearest thousand = 36000

             27677 estimated to the nearest  thousand = 28000

          ∴ The required estimation = (36000 ‒ 28000) = 8000

    (31). 47005 estimated to the nearest thousand = 47000

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             39488 estimated to the nearest  thousand = 39000

          ∴ The required estimation = (47000 ‒ 39000) = 8000