RS Aggarwal 2021-2022 for Class 6 Maths Solutions Chapter 7- Decimal
RS Aggarwal Class 6 Math Solution Chapter 7- Decimal Exercise 7D is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.Rs Aggarwal Class 6 Math Solution Chapter 7- Decimal
Exercise 7D
Subtract:
1. 27.86 from 53.74
Solution:
= 53.74 – 27.86
= 25.88 Ans.
Working in column method:
53.74
– 27.86
25.88
2. 64.98 from 103.87
Solution:
= 103.87 – 64.98
= 38.89 Ans.
Working in column method:
103.87
– 64.98
38.89
3. 59.63 from 92.4
Solution:
= 92.40 – 59.63
= 32.77 Ans.
Working in column method:
92.40
– 59.63
32.77
4. 56.8 from 204
Solution:
= 204.0 – 56.8
= 147.2 Ans.
Working in column method:
204.00
– 56.80
147.20
5. 127.38 from 216.2
Solution:
= 216.20 – 127.38
= 88.82 Ans.
Working in column method:
216.20
– 127.38
088.82
6. 39.875 from 70.68
Solution:
= 70.680 – 39.875
= 30.805 Ans.
Working in column method:
70.680
– 39.875
30.805
7. 348.237 from 523.12
Solution:
= 523.120 – 348.237
= 174.883 Ans
Working in column method:
523.120
– 348.237
174.883
8. 458.573 from 600
Solution:
= 600.000 – 458.573
= 141.427 Ans.
Working in column method:
600.000
– 458.573
141.427
9. 149.456 from 206.321
Solution:
= 206.321 – 149.456
= 56.865 Ans.
Working in column method:
206.321
– 149.456
56.865
10. 0.612 from 3.4
Solution:
= 3.400 – 0.612
= 2.788 Ans
Working in column method:
3.400
– 0.612
2.788
Simplify:
11. 37.600 + 72.850 – 58.678 – 6.090
Solution:
= (37.600 + 72.850) – (58.678 + 6.090)
= 110.450 – 64.768
= 45.682
Working:
37.60 58.678 + 72.85 + 6.090 110.45 64.768
110.450 − 64.768 45.682
12. 75.3 – 104.645 + 178.96 – 47.9
Solution:
(Converting into like decimals)
= 75.300 – 104.645 + 178.960 – 47.900
= 75.300 + 178.960 – 104.645 – 47.900
= (75.300 + 178.960) – (104.645 + 47.900)
= 254.260 – 152.545
= 101.715 Ans.
Working:
178.96 104.645 + 75.30 + 47.900 254.26 152.545
254.260 − 152.545 101.715
13. 213.4 – 56.84 – 11.87 – 16.087
Solution:
(Converting into like decimals)
= 213.400 – 56.840 – 11.870 – 16.087
= 213.400 – (56.840 + 11.870 + 16.087)
= 213.400 – 84.797
= 128.603 Ans.
Working:
56.840 213.400 11.870 − 84.797
+ 16.087 128.603
84.797
14. 76.3 – 7.666 – 6.77
Solution:
(Converting into like decimals)
= 76.300 – 7.666 – 6.770
= 76.300 – 14.436
= 61.864 Ans.
15. What is to be added to 74.5 to get 91?
Solution:
In order to get the required number, we have to subtract 74.5 from 91. Required number = 91 – 74.5 = 91.0 – 74.5 = 16.5 Ans.
Working:
91.0 − 74.5 16.5 Thus, 16.5 is the required number.
16. What is to be subtracted from 7.3 to get 0.862?
Solution:
In order to get the required numbers, we have to subtract 0.862 from 7.3. Required number = 7.3 – 0.862 = 7.300 – 0.862 = 6.438 Ans.
Working:
7.300 − 0.862 6.438 Thus, 6.438 is the required number.
17. By how much should 23.754 be increased to get 50?
Solution:
In order to get the required number, we have to subtract 23.754 from 50 Required number = 50 – 23.754 = 50.000 – 23.754 = 26.246 Ans.
Working:
50.000 − 23.754 26.246
18. By how much should 84.5 be decreased to get 27.84?
Solution:
In order to get the required number, we should subtract 27.84 from 84.5 Required number = 84.5 – 27.84 = 84.50 – 27.84 = 56.66 Ans.
Working:
84.50 − 27.84 56.66
19. If the school bags of Neelam and Garima weigh 6 kg 80 g and 5 kg 265 g respectively, whose bag is heavier and by how much?
Solution:
Weight of Neelam’s bag = 6 kg 80 g Weight of Garima's bag = 5 kg 265 g Difference in their weights = 6 kg 80 g – 5 kg 265 g = 6.080 kg – 5.265 kg = 0.815 kg = 815 g Neelam’s bag is heavier by 815 g Ans.
20. Kunal purchased a notebook for Rs. 19.75, a pencil for Rs. 3.85 and a pen for
Rs. 8.35 from a book shop. He gave a 50-rupee note to the shopkeeper. What amount did he get back?
Solution:
Cost of the notebook = Rs 19.75 Cost of the pencil = Rs 3.85 Cost of the pen = + Rs 8.35 Total cost payable = Rs 31.95 Total money paid = Rs. 50.00 Total money spent = − Rs. 31.95 Balance = Rs. 18.05 Thus, Kunal got back Rs 18.05 from the shopkeeper.
21. Sunita purchased 5 kg 75 g of fruits and 3 kg 465 g of vegetables, and put them
in a bag. If this bag with these contents weighs 9 kg, find the weight of the empty bag.
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