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RS Aggarwal Class 6 Maths Chapter 5- Fractions Exercise 5F

RS Aggarwal 2021-2022 for Class 6 Maths Chapter 5- Fractions

RS Aggarwal Class 6 Math Solution Chapter 5- Fractions  Exercise 5F is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily.  RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.


 Rs Aggarwal Class 6 Math Solution Chapter 5- Fractions 


 Exercise 5F


Find the difference:     

1. 5818

Solution: 

    5818

    = 518

    =  4182

    =  12


2. 712512

Solution: 

    712512

    = 7512

    =  21126

    =  16


3. 437 − 247

Solution: 

    437 − 247

    = 317187

    = 31187

    =  137

    = 167


4. 5649

Solution: 

     5649

    L.C.M of 6 and 9 = 18

    = 15818

    =  718


5. 1238

Solution: 

     1238

    L.C.M of 2 and 8 = 8

    = 438

    =  18


6. 58712

Solution: 

     58712

    L.C.M of 8 and 12 = 24

    = 151424

    =  124


7. 279 − 1815

Solution: 

    279 − 1815

    = 2592315

     L.C.M of 9 and 15 = 45

    = 1256945

    =  5645

    = 11145


8. 358 − 2512

Solution: 

    358 − 2512

    = 2982912

     L.C.M of 8 and 12 = 24

    = 875824

    =  2924

    = 1524


9. 2310 − 1715

Solution: 

    2310 − 1715

    = 23102215

     L.C.M of 10 and 15 = 30

    = 694430

    =  255306

    = 56


10. 623 − 334

Solution: 

    623 − 334

    = 203154

     L.C.M of 3 and 4 = 12

    = 804512    

    = 3512


11. 7 − 523

Solution: 

    7 − 523

    = 71  − 173

     L.C.M of 1 and 3 = 3

    = 21173    

    = 43

    = 113


12. 10 − 638

Solution: 

    10 − 638

    = 101  − 518

     L.C.M of 1 and 8 = 8

    = 80518    

    = 298

    = 358


13. 5649 + 23

Solution: 

    5649 + 23

    L.C.M of 6, 9 and 3 = 18

    =  158+1218

    = 278 18

    = 1918

    = 1118


14. 58 + 34712

Solution: 

     58 + 34712

    L.C.M of 8, 4 and 12 = 24

    =  15+18 1424

    = 3314 24

    = 1924


15. 2 + 111559

Solution: 

     2 + 111559

    =  21 + 111559

    L.C.M of 1, 15 and 9 = 45

    =  90+33 2545

    = 1232545

    = 9845

    = 2845

    

16. 534 − 4512 + 316

Solution: 

    534 − 4512 + 316

    = 2345312 + 196

    L.C.M of 4, 12 and 6 = 12

    =  6953+3812

    = 1075312

    = 549122

    = 92

    =  412


17. 2 + 5710 − 31415

Solution: 

     2 + 5710 − 31415

    =  21 + 57105915

    L.C.M of 1, 10 and 15 = 30

    =  60+171 11830

    = 23111830

    = 11330

    = 32330


18. 8 − 312 − 214

Solution: 

     8 − 312 − 214

    =  81 −  7294

    L.C.M of 1, 2 and 4 = 4

    =  32  1494

    = 32234

    = 94

    = 214


19. 856 − 338 + 2712

Solution: 

    534 − 4512 + 316

    = 2345312 + 196

    L.C.M of 4, 12 and 6 = 12

    =  6953+3812

    = 1075312

    = 549122

    = 92

    =  412


20. 616 − 515 + 313

Solution: 

    616 − 515 + 313

    = 376265 + 103

    L.C.M of  6, 5 and 3 = 30

    =  185156+10030

    = 28515630

    = 129433010

    = 4310

    =  4310


21. 3 + 115 + 23715

Solution: 

     3 + 115 + 23715

    = 31 + 65 + 23 − 715

    L.C.M of  1, 5, 3 and 15 = 15

    =  45+18+10715

    = 73715

    = 6622155

    = 225

    =  425


22. What should be added to 923 to get 19?

Solution: 

    Let the required number be x

    Now, according to question

    923 + x = 19

    ⇒ 293 + x = 19

    ⇒ x = 19 − 293 

    ⇒ x = 191293 

    ⇒ x = 57 293

     ⇒ x = 283

     ⇒ x = 913

    Hence, the required number is 913


23. What should be added to 6715 to get 815?

Solution: 

    Let the required number be x

    Now, according to question

    6715 + x = 815

    ⇒ 9715 + x = 415

    ⇒ x = 415 − 9715 

    ⇒ x = 123 9715

     ⇒ x = 2615

     ⇒ x = 11115

    Hence, the required number is 11115


24. Subtract the sum of 359 and 313 from the sum of 556 and 419.

Solution: 

        (556 + 419) −  (359 + 313)

    =  (356 + 379) −  (329 + 103)

    =  (105+7418)  −  (32+309)

    =  17918 −  629

    =   17912418

    =   5518

    =  3 118


25. Of 34 and 57, which is greater and by how much ?

Solution: 

    First we compare 34 and 57

    By cross multiply

    3 × 7 = 21 and 4 × 5 = 20

    Clearly, 21 > 20

    34 > 57

     Now, Required difference:

     = 34 −  57

          L.C.M of 4 and 7 = 28

     = 212028

     = 128

    Hence, 34 is greater than 57 by 128


26. Mrs. Soni bought 712 liters of milk. Out of this milk, 534 liters was consumed. How             much milk is left with her?

Solution: 

    Milk bought by Mrs. Soni = 712 liters

    Milk consumed by her = 534 litres

    Milk left with her = 712 − 534

                         = 152234

                 = 30234

                 = 74 litres

                                 = 134 litres


27. A film show last for 313 hours. Out of this time, 134 hours are spent on advertisements.         What was the actual duration of the film?

Solution: 

    Total duration of a film show = 313 hours.

    Time spent on advertisement = 134 hours

    The actual duration of the film = 313 − 134

                                                          10374

                                                           402112

                                                          1912

                                                          1712 hours


28. In one day, a rickshaw puller earned Rs. 13712. Out of this money, he spent Rs. 5634 on         food. How much money is left with him?

Solution: 

    Rickshaw puller earned in a day = Rs. 13712 = Rs.2752

    He spent on food = Rs. 5634 = Rs.2274

    Money left with him = 27522274

                                     5502274

                                    =  3234

                                    = Rs. 8034


29. A piece of wire, 234 metres long, broken into two pieces. One piece is 58 metre long.             How long is the other piece?

Solution: 

    Total length of wire = 234m = 114m

    Length of one piece of wire  =  58

    Length of other piece of wire  = 114 − 58

                                                     2258

                                                     =  178

                                                     = 218m




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