RS Aggarwal Class 6 Maths Chapter 3 - Whole Number Exercise 3E

 

RS Aggarwal 2021-2022 for Class 6 Maths Chapter 3 - Whole Number 

Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number Exercise 3E is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily.  RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.

Rs Aggarwal Class 6 Math Solution Chapter 3 Whole Number

Exercise 3E

1: Divide and check your answer by the corresponding multiplication in each of the following: 

    (i) 1936 ÷ 16

    (ii) 19881 ÷ 47

    (iii) 257796 ÷ 341

    (iv) 612846 ÷ 582

    (v) 34419 ÷ 149

    (vi) 39039 ÷ 1001

Solution:

    (i) 

     Dividend = 1936, Divisor = 36 , Quotient = 53 , Remainder = 28

Check:

     Dividend = Divisor × Quotient + Remainder  

           1936 =  36 × 53 + 28

            1936 = 1908 + 28

            1936 = 1936

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

    (ii) 

    Dividend = 19881, Divisor = 47 , Quotient = 423, Remainder = 0

Check:

    Dividend = Divisor × Quotient + Remainder  

           19881 =  47 × 423 + 0

            1936 = 19881 + 0

            1936 = 19881

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(iii) 

    Dividend = 257796, Divisor = 341 , Quotient = 756, Remainder = 0

Check:    

    Dividend = Divisor × Quotient + Remainder  

          257796 =  341 × 756 + 0

          257796 = 257796 + 0

          257796 = 257796

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(iv)  

    Dividend = 612846 , Divisor = 582, Quotient = 1053 , Remainder = 0

Check :  

    Dividend = Divisor × Quotient + Remainder  

       612846 =  582 × 1053 + 0

      612846 = 612846 + 0

      612846 = 612846

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(v) 

    Dividend = 34419, Divisor = 149 , Quotient = 231, Remainder = 0

Check : 

    Dividend = Divisor × Quotient + Remainder  

       34419 =  149 × 231 + 0

      34419 =  34419 + 0

      34419 =  34419

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(vi) 

    Dividend = 39039 , Divisor = 1001 , Quotient = 39 , Remainder = 0

Check : 

    Dividend = Divisor × Quotient + Remainder  

       39039 =  1001 × 39 + 0

      39039 =  39039 + 0

      39039 = 39039

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

2: Divide and find out the quotient and remainder. Check your answer:

    (i) 6971÷ 47

    (ii) 4178 ÷ 35

    (iii) 36195 ÷ 153

    (iv) 93575 ÷ 400

    (v) 23025 ÷ 1000

    (vi) 16135 ÷ 875

Solution:

(i) 

    Quotient = 148 and Remainder = 15

Check : 

    Dividend = Divisor × Quotient + Remainder  

       6971 =  47 × 148 + 15

      6971 =  6956 + 15

      6971 = 6971

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(ii) 

    Dividend = 119 and Remainder = 13

Check : 

    Dividend = Divisor × Quotient + Remainder  

       4178 =  35 × 119 + 13

      4178 =  4165 + 13

      4178 = 4178

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(iii) 

    Quotient = 236 and Remainder = 87

Check : 

    Dividend = Divisor × Quotient + Remainder  

       36195 =  153 × 236 + 87

      36195 =  3608 + 87

      36195 = 36195

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(iv) 

    Quotient = 233 and Remainder = 375

Check : 

    Dividend = Divisor × Quotient + Remainder  

       93575 =  400 × 233 + 375

      93575 =  93200 + 375

      93575 = 93575

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(v) 

    Quotient = 23 and remainder = 25

Check : 

    Dividend = Divisor × Quotient + Remainder  

       23025 =  1000 × 23 + 25

      23025 =  23000 + 25

      23025 = 23025

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified.

(vi) 

    Quotient = 18 and Remainder = 385

Check : 

    Dividend = Divisor × Quotient + Remainder  

       16135 =  875 × 18 + 385

      16135 =  15750 + 385

      16135 = 16135

    Hence, Dividend = Divisor × Quotient + Remainder  is Verified. 

3: Find the value of

    (i) 65007 ÷ 1

    (ii) 0 ÷ 879

    (iii) 981+ 5720 ÷ 10

    (iv) 1507 - 625 ÷ 25

    (v) 32277 ÷ (648 - 39)

    (vi) 1573 ÷ 1573 - 1573 ÷ 1573

Solution:

(i) 65007 ​÷ 1 = 65007

    Because, Any number (non zero) divided by 1 gives the number itself.

(ii) 0 ​÷ 879  = 0

    Because, 0 divided by any number gives 0

(iii) 981 + 5720 ​÷ 10

    = 981 + (5720 ​÷ 10)                               (Following DMAS property)

    = 981 + 572

    = 1553

(iv) 1507 − (625 ÷ 25)                             (Following BODMAS property)

    = ​​1507 − 25

    = 1482

(v) 32277 ÷ (648 − 39)                                 (Following BODMAS property)

    = ​32277 ÷ (609)

    =  53

(vi)  (1573 ÷ 1573) − (1573 ÷ 1573)            (Following BODMAS property)

    = 1 − 1

    = 0 

4: Find a whole number n such that n ÷ n = n

Solution: 

    Given:  n ÷ n = n

    ⇒  `frac\{n}{n}` = n 

    ​⇒  n = `n^2`

    i.e., the whole number n is equal to `n​^2`

    ∴ The given whole number must be 1.    

5: The product of two numbers is 504347. If one of the numbers is 317, find the other.

Solution:

    The product of two numbers is 504347

    One of the numbers is 317

    Other Number = `frac\{cancel 504347 ^1591}{cancel 317}`

                         = 1591

    ∴ The other number is 1591.

6: On dividing 59761 by a certain number, the quotient is 189 and the remainder is 37. Find the divisor.

Solution:

    Dividend = 59761, quotient = 189, remainder = 37 and divisor = ?

    Dividend = divisor × quotient + remainder

    ⇒ 59761 = divisor × 189 + 37

    ⇒ 59761 − 37 = divisor × 189

    ⇒ 59724 = divisor × 189

    ⇒ Divisor = 59724 ​÷ 189                  

    Hence, Divisor =316

7: On dividing 55390 by 299, the remainder is 75. Find the quotient, using the division algorithm.

Solution:

    Here, Dividend = 55390, Divisor = 299 and Remainder = 75

    We have to find the quotient.

    Now, Dividend = Divisor × Quotient + Remainder 

    ⇒ 55390 = 299 × Quotient + 75

    ⇒ 55390 − 75 = 299 × Quotient

    ⇒ 55315 = 299 × Quotient 

    ⇒ Quotient = 55315 ​÷ 299         

    Hence, Quotient = 185

8: What least number must be subtracted from 13601 to get a number exactly divisible by 87?

Solution: 

    First, we will divide 13601 by 87.

    Remainder = 29

    So, 29 must be subtracted from 13601 to get a number exactly divisible by 87.

    ∴ Require least number = 29

9: What least number must be added to 1056 to get a number exactly divisible by 23 ?

Solution:

    First, we will divide 1056 by 23.

    Required number = 23 − 21 = 2

    So, 2 must be added to 1056 to make it exactly divisible by 23.

10: Find the largest 4-digit number divisible by 16.

Solution: 

    The largest four-digit number = 9999

    Now, We divide 9999 by 16

    Here, we get remainder =15

   Therefore, 15 must be subtracted from 9999 to get the largest four digit number that is divisible by 16.

    So, Require 4 digit number = 9999 − 15 = 9984

11: Divide the largest 5-digit number by 653. Check your answer by division algorithm.

Solution: 

    Largest five-digit number =99999

    Dividend = 99999, Divisor = 653, Quotient = 153 and Remainder = 90

Check: 

    Dividend = Divisor × Quotient + Remainder

       99999   = 653 × 153 + 90

        99999  = 99909 + 90

        99999  = 99999

    ∴ Dividend = Divisor × Quotient + Remainder ,    Verified.

12: Find the least 6-digit number exactly divisible by 83.

Solution:

    The least 6-digit number = 100000

    Now, dividend = 100000 and divisor = 83

    ∴ Require the least 6-digit number exactly divisible by 83

    = 100000 + (83 - 68)

    = 100000 + 15

    = 100015

13. 1 dozen bananas cost Rs. 29. How many dozens can be purchased for Rs. 1392?

Solution:

    Cost of 1 dozen bananas = Rs 29

    Number of dozens purchased for Rs 1392 = 1392 ÷ 29

    Hence, 48 dozen of bananas can be purchased with Rs. 1392.

14: 19625 trees have been equally planted in 157 rows. Find the number of trees in each row.

Solution:

    Number of trees  = 19625

    Number of rows = 157

    Trees planted in 1 row = 19625 ÷ 157

    ∴ 125 trees are planted in each row.    

15: The population of a town is 517530, If one out of every 15 is reported to be literate, find how many literate persons are there in the town.

Solution: 

     The population of a town = 517530

     Number of literate person = `frac\{1}{15}` of 517530

                                               =  517530 ÷ 15

    ∴ Total number of literate person = 34502

16: The cost price of 23 colour television sets is Rs. 570055. Determine the cost price of each TV set if each costs the same.

Solution: 

    Cost of 23 colour television = Rs. 570055

    Cost of 1 colour television = 570055 ÷ 23

    ∴ Cost of 1 TV set = Rs. 24785