RS Aggarwal 2021-2022 for Class 6 Maths Chapter 1 - Number System
RS Aggarwal Class 6 Math Solution Chapter 1 Number System Exercise 1C is available here. RS Aggarwal Class 6 Math Solutions are solved by expert teachers in step by step, which help the students to understand easily. RS Aggarwal textbooks are responsible for a strong foundation in Maths. These textbook solutions help students in exams as well as their daily homework routine. The solutions included are easy to understand, and each step in the solution is described to match the students’ understanding.
RS Aggarwal Class 6 Math Solution Chapter 1 Number System
EXERCISE 1C
1. The number of persons who visited the holy shrine of Mata Vaishno Devi during last two consecutive years was 13789509 and 12976498 respectively. How many persons visited the shrine during these two years?
Solution:
Persons who visited the holy shrine in the first year = 13789509
Persons who visited the holy shrine in the second year = 12976498
∴ Total persons visited the holy shrine during these two years = 13789509 + 12976498
= 26766007
2. Last year, three sugar factories in a town produced 24809565 bags, 18738576 bags and 9564568 bags of sugar respectively. How many bags were produced by all the three factories during last year?
Solution:
Bags of sugar produced by the first factory in last year = 24809565
Bags of sugar produced by the second factory in last year = 18738576
Bags of sugar produced by the third sugar factory in last year = 9564568
So, Total bags of sugar produced by the factories = 24809565 + 18738576 + 9564568
= 53112709
3. A number exceeds 37684955 by 3615045. What is that number?
Solution:
New number = Sum of 37684955 and 3615045
= 37684955 + 3615045
= 41300000
4. There were three candidates in an election. They received 687905 votes, 495086 votes and 93756 votes respectively. The number of invalid votes was 13849. If 25467 persons did not vote, find how many votes were registered.
Solution:
Total votes received by the three candidates = 687905 + 495086 + 93756
=1276747
Number of invalid votes = 13849
Number of persons who did not vote = 25467
∴ Total number of registered voters = 1276747 + 13849 + 25467 = 1316063
5. A survey conducted on an Indian state shows that 1623546 people have only primary education: 9768678 people have secondary education; 6837954 people have higher education and 2684536 people are illiterate. If the number of children below the age of school admission is 698781. Find the total population of the state.
Solution:
People who had only primary education = 1623546
People who had secondary education = 9768678
People who had higher education = 6837954
Illiterate people in the state = 2684536
Children below the age of school admission = 698781
∴ Total population of the state = 1623546 + 9768678 + 6837954 + 2684536 + 698781
= 21613495
6. In a particular year a company produced 8765435 bicycles. Next year, the number of bicycles produced was 1378689 more than those produced in the preceding year. How many bicycles were produced during the second year? How many bicycles were produced during these two years?
Solution:
Bicycles produced by the company in the first year = 8765435
Bicycles produced by the company in the second year = 8765435 + 1378689
= 10144124
∴ Total number of bicycles produced during these two years = 8765435 + 10144124
= 18909559
7. The sale receipt of a company during a year was 20956480. Next year, it increased by 6709570. What was the total sale receipt of the company during these two years?
Solution:
Sale receipts of a company during the first year = Rs 20956480
Sale receipts of the company during the second year = Rs 20956480 + Rs 6709570
= Rs 27666050
∴ Total number of sale receipts during these two years = Rs 20956480 + Rs 27666050
= Rs 48622530
8. The total population of a city is 28756304. If the number of males is 16987059, find the number of females in the city.
Solution:
Total population of the city = 28756304
Number of males in the city = 16987059
∴ Number of females in the city = 28756304 ‒ 16987059
= 11769245
9. By how much is 13246510 larger than 4658642?
Solution:
Required number = 13246510 ‒ 4658642 = 8587868
∴ 13246510 is larger than 4658642 by 8587868.
10. By how much is 5643879 smaller than one crore?
Solution:
Required number = 1 crore ‒ 564387
= 10000000 ‒ 5643879
= 4356121
∴ 5643879 is smaller than one crore by 4356121.
11. What number must be subtracted from 11010101 to get 2635967?
Solution:
11010101 ‒ required number = 2635967
Thus, required number = 11010101 ‒ 2635967
= 8374134
∴ The number 8374134 must be subtracted from 11010101 to get 2635967.
12. The sum of two numbers is 10750308. If one of them is 8967519, what is the other number?
Solution:
Sum of the two numbers = 10750308
One of the number = 8967519
∴ The other number = 10750308 ‒ 8967519
= 1782789
13. A man had ₹ 20000000 with him. He spent ₹13607085 on buying a school building. How much money is left with him?
Solution:
Initial amount with the man = Rs 20000000
Amount spent on buying a school building = Rs 13607085
∴ Amount left with the man = Rs 20000000 ‒ Rs 13607085 = Rs 6392915
14. A society needed ₹ 18536000 to buy a property. It collected ₹ 7253840 as membership fee. took a loan of ₹ 5675450 from a bank and collected ₹ 2937680 as donation. How much is the society still short of ?
Solution:
Money need by the society to buy the property = Rs 18536000
Amount collected as membership fee = Rs 7253840
Amount taken on loan from the bank = Rs 5675450
Amount collected as donation = Rs 2937680
∴ Amount of money short = Rs 18536000 ‒ (Rs 7253840 + Rs 5675450 + Rs 2937680)
= Rs 18536000 ‒ Rs 15866970
= Rs 2669030
15. A man had ₹ 10672540 with him. He gave ₹ 74836980 to his wife, ₹ 3964790 to his son and the rest to his daughter. How much money was received by the daughter?
Solution:
Initial amount with the man = Rs 10672540
Amount given to his wife = Rs 4836980
Amount given to his son = Rs 3964790
∴ Amount received by his daughter = Rs 10672540 ‒ (Rs 4836980 + Rs 3964790)
= Rs 10672540 ‒ Rs 8801770
= Rs 1870770
16. The cost of a chair is ₹ 1485.How much will 469 such chairs cost?
Solution:
Cost of one chair = Rs 148
Cost of 469 chairs = Rs 1485 × 469
= Rs 696465
∴ Cost of 469 chairs is Rs 696465.
17. How much money was collected from 1786 students of a school for a charity show if each student contributed ₹ 625?
Solution:
Contribution from one student for the charity program = Rs 625
Contribution from 1786 students = Rs 625 x 1786 = Rs 1116250
∴ Rs 1116250 was collected from 1786 students for the charity program.
18. A factory produces 6985 screws per day. How many screws will it produce in 358 days?
Solution:
Number of screws produced in one day = 6985
Number of screws produced in 358 days = 6985 x 358
= 2500630
∴ The factory will produce 2500630 screws in 358 days.
19. Mr Bhaskar saves ₹ 8756 every month. How much money will he save in 13 years?
Solution:
As we know that
1 year = 12 months
13 years = 13 x 12 = 156 months
Now, we have:
Amount saved by Mr Bhaskar in one month = Rs 8756
Amount saved in 156 months = Rs 8756 × 156 = Rs 1365936
∴ Mr Bhaskar will save Rs 1365936 in 13 years.
20. A scooter costs ₹ 736725. How much will 487 such scooters cost?
Solution:
Cost of one scooter = Rs 36725
Cost of 487 scooter = Rs 36725 × 487
= Rs 17885075
∴ The cost of 487 scooters will be Rs 17885075.
21. An aeroplane covers 1485 km in 1 hour. How much distance will it cover in 72 hours?
Solution:
Distance covered by the aeroplane in one hour = 1485 km
Distance covered in 72 hours = 1485 km × 72 = 106920 km
∴ The distance covered by the aeroplane in 72 hours will be 106920 km
22. The product of two numbers is 13421408. If one of the numbers is 364, find the other.
Solution:
Product of two numbers = 13421408
One of the number = 364
∴ The other number = 13421408 ÷ 364
= 36872.
23. If 36 flats cost ₹ 68251500, what is the cost of each such flat?
Solution:-
Cost of 36 flats = Rs 68251500
Cost of one flat = Rs 68251500 ÷ 36
= Rs 1895875
∴ Each flat costs Rs 1895875.
24. The mass of a cylinder filled with gas is 30 kg 250 g and the mass of the empty cylinder is 14 kg 480 g. How much is the mass of the gas contained in it?
Solution:
As we know that 1 kg = 1000 g
Now, mass of the gas-filled cylinder = 30 kg 250 g = 30.25 kg
Mass of an empty cylinder = 14 kg 480 g = 14.48 kg
∴ Mass of the gas contained in the cylinder = 30.25 kg ‒ 14.48 kg
= 15.77 kg = 15 kg 770 g
25. From a cloth 5 m long., a piece of length 2 m 85 cm is cut off. What is the length of the remaining piece?
Solution:
As we know that 1 m = 100 cm
Length of the cloth = 5 m
Length of the piece cut off from the cloth = 2 m 85 cm
∴ Length of the remaining piece of cloth = 5 m ‒ 2.85 m
= 2.15 m = 2 m 15 cm
26. In order to make a shirt, a length of 2 m 75 cm of cloth is needed. How much length of the cloth will be required for 16 such shirts?
Solution:
As we know that 1 m = 100 cm
Now, length of the cloth required to make one shirt = 2 m 75 cm
Length of the cloth required to make 16 such shirts = 2 m 75 cm × 16
= 2.75 m × 16
= 44 m
∴ The length of the cloth required to make 16 shirts will be 44 m.
27. For making 8 trousers of the same size, 14 m 80 cm of cloth is needed. How much cloth will be required for each such trouser?
Solution:
As we know that 1 m = 100 cm
Cloth needed for making 8 trousers = 14 m 80 cm
Cloth needed for making 1 trousers = 14 m 80 cm ÷ 8
= 14 .8 m ÷ 8
= 1.85 m = 1 m 85 cm
∴ 1 m 85 cm of cloth will be required to make one shirt.
28. The mass of a brick is 2 kg 750g. What is the total mass of 14 such bricks?
Solution:
As we know that 1 kg = 1000 g
Now, mass of one brick = 2 kg 750 g
∴ Mass of 14 such bricks = 2 kg 750 g × 14
= 2.75 kg × 14
= 38.5 kg = 38 kg 500 g
29. The total mass of 8 packets, each of the same size, is 10 kg 600g. What is the mass of each such packet?
Solution:
We know that 1 kg = 1000 g
Now, total mass of 8 packets of the same size = 10 kg 600 g
∴ Mass of one such packet = 10 kg 600 g ÷ 8
= 10.6 kg ÷ 8
= 1.325 kg = 1 kg 325 g
30. A rope of length 10 m has been divided into 8 pieces of the same length. What is the length of each piece?
Solution:
Length of the rope divided into 8 equal pieces = 10 m
Length of one piece = 10 m ÷ 8
= 1.25 m = 1 m 25 cm [∵ 1 m = 100 cm]
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